9x^-40x^2+16=0

Solution for 9x^-40x^2+16=0 equation:

9x^-40x^2+16=0

We add all the numbers together, and all the variables

-40x^2+9x+16=0

a = -40; b = 9; c = +16;
Δ = b2-4ac
Δ = 92-4·(-40)·16
Δ = 2641
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{2641}}{2*-40}=\frac{-9-\sqrt{2641}}{-80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{2641}}{2*-40}=\frac{-9+\sqrt{2641}}{-80}
$